Question

i. $0.1Methanol$
ii. $0.1M{Ba}_3{\left(P{O}_4\right)}_3$
iii.$0.1M{Na}_{2}S{O}_4$
Increasing order of freezing point

• A. $\left(ii\right)<\left(iii\right)<\left(i\right)$
• B. $\left(iii\right)<\left(ii\right)<\left(i\right)$
• C. $\left(i\right)<\left(ii\right)<\left(iii\right)$
• D. $\left(ii\right)<\left(i\right)<\left(iii\right)$

Answer 1

The correct option is A $\left(ii\right)<\left(iii\right)<\left(i\right)$

Freezing point is higher if $\Delta T_f$ is lower (depends on $m_{effective}$)
$\therefore 0.1m{Ba}_3{\left(P{O}_4\right)}_2<0.1m{Na}_{2}S{O}_4<0.1mEthanol$.