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Byju's Answer
Standard XII
Physics
AC Applied to a Resistor
WR =8 Ωi =15 ...
Question
i
=
15
sin
ω
t
+
20
cos
ω
t
.
Alternating current
i
is passed through a resistance of
8
Ω
. Find the heat developed across R in 10 seconds.
A
25
×
10
3
J
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B
125
×
10
2
J
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C
625
×
10
2
J
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D
5
×
10
4
J
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Solution
The correct option is
A
25
×
10
3
J
i
=
15
sin
ω
t
+
20
cos
ω
t
=
25
{
15
25
sin
ω
t
+
20
25
cos
ω
t
}
=
25
{
sin
ω
t
cos
53
∘
+
cos
ω
t
sin
53
∘
}
i
=
25
sin
(
ω
t
+
53
∘
)
i
r
m
s
=
25
√
2
H
e
a
t
(
Q
)
=
P
o
w
e
r
×
t
=
i
2
r
m
s
R
t
Q
=
i
2
r
m
s
R
t
=
(
25
√
2
)
2
8
×
10
=
625
2
×
8
×
10
=
2500
×
10
=
25
×
10
3
J
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Q.
i
=
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