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Question

I. 20x217x+3=0
II. 20y29y+1=0

A
x>y
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B
x<y
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C
xy
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D
xy
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E
x=y or cannot be established
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Solution

The correct option is C xy
(4x1)(5x3)=0x=14,35(4y1)(5y1)=0y=14,1535,14,14,15xy

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