Question

$I.2x^2+23x+63=0II.4y^2+19y+21=0$

• A. $x<y$
• B. $x>y$
• C. $x\ge y$
• D. $x\le y$
• E. The relationship between $x$ and $y$ cannot be established.

Answer 1

The correct option is A $x<y$

Equation I:-
$2x^2+23x+63=0$
$2x^2+14x+9x+63=0$
$2x(x+7)+9(x+7)=0$
$(x+7)(2x+9)=0$
$x=-7,x=-\frac{9}{2}$
Equation II:-
$4y^2+19y+21=0$
$4y^2+12y+7y+21=0$
$\left(4y\right(y+3)+7(y+3)=0$
$(y+3)(4y+7)=0$
$\therefore y=-3,y=-\frac{7}{4}$
Hence $x<y$