I- 2 x2-7 x-6-0II- 4 y 2-9A- If x-yB- If x - y C- If x - yD- If x-yE- If x - y

The correct option is E If x ≥ yEquation I 2x^2 7x+6=0 ⇒ 2x^2 4x 3x+6=0 ⇒ 2x(x 2) 3(x 2)=0 ⇒ (2x 3)(x 2)=0 ⇒ x= 3/2 or 2 Equation II 4y^2 = 9 ⇒ y^2 = 9/4 ⇒ y ...

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Byju's Answer

Standard XII

Mathematics

Derivative of Standard Functions

I. 2 x2-7 x+6...

Question

I. $2 x^{2} - 7 x + 6 = 0$
II. $4 y^{2} = 9$

x < y

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x \leq y

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x = y

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x > y

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x \geq y

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Solution

The correct option is E If $x \geq y$
Equation I
$2 x^{2} - 7 x + 6 = 0$
$\Rightarrow 2 x^{2} - 4 x - 3 x + 6 = 0$
$\Rightarrow 2 x (x - 2) - 3 (x - 2) = 0$
$\Rightarrow (2 x - 3) (x - 2) = 0$
$\Rightarrow x = \frac{3}{2}$ or $2$

Equation II
$4 y^{2} = 9$
$\Rightarrow y^{2} = \frac{9}{4}$
$\Rightarrow y = \pm \frac{3}{2}$
Hence, $y \leq x$

Suggest Corrections

I. 2x2−7x+6=0 II. 4y2=9

The correct option is E If x≥yEquation I 2x2−7x+6=0 ⇒2x2−4x−3x+6=0 ⇒2x(x−2)−3(x−2)=0 ⇒(2x−3)(x−2)=0 ⇒x=32 or 2 Equation II 4y2=9 ⇒y2=94 ⇒y=±32 Hence, y≤x

I. $2 x^{2} - 7 x + 6 = 0$
II. $4 y^{2} = 9$