Question

$I.4x^2+23x+45=0II.3y^2-19y+28=0$

• A. $x<y$
• B. $x>y$
• C. $x\ge y$
• D. $x\le y$
• E. Relationship between x and y cannot be established

Answer 1

The correct option is E Relationship between x and y cannot be established

Equation I
$4x^2+23x+45=0$
$4x^2-20x-9x+45=0$
$4x(x-5)-9(x-5)=0$
$(4x-9)(x-5)=0$
$x=5,x=\frac{9}{4}$
Equation II
$3y^2-19y+28=0$
$3y^2-12y-7y+28=0$
$3y(y-4)-7(y-4)=0$
$(3y-7)(y-4)=0$
$y=4,y=\frac{7}{3}$
Hence, relationship between x and y cannot be established.