I- 6 x- 2-13 x-21-0II- 5 y - 2-22 y-21-01

The correct option is C x gt; yEquation I 6x^2+41x+63=0 ⇒ 6x^2+27x+14x+63=0 ⇒ 3x(2x+9)+7(2x+9)=0 ⇒ (3x+7)(2x+9)=0 ∴ x= 7/3, x = 9/2 Equation II 4y^2+8y+3=0 ...

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Byju's Answer

Standard XII

Mathematics

Derivative of Standard Functions

I. 6 x∧ 2+13 ...

Question

$I . 6 x^{2} + 13 x + 21 = 0 I I . 5 y^{2} - 22 y + 21 = 0$

x \leq y

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x < y

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x > y

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x \geq y

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None of these

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Solution

The correct option is C $x > y$
Equation I
$6 x^{2} + 41 x + 63 = 0$
$\Rightarrow 6 x^{2} + 27 x + 14 x + 63 = 0$
$\Rightarrow 3 x (2 x + 9) + 7 (2 x + 9) = 0$
$\Rightarrow (3 x + 7) (2 x + 9) = 0$
$∴ x = - \frac{7}{3}, x = \frac{- 9}{2}$
Equation II
$4 y^{2} + 8 y + 3 = 0$
$\Rightarrow 4 y^{2} + 6 y + 2 y + 3 = 0$
$\Rightarrow 2 y (2 y + 3) + 1 (2 y + 3) = 0$
$\Rightarrow (2 y + 1) (2 y + 3) = 0$
$∴ y = - \frac{1}{2}, - \frac{3}{2}$
Hence, x < y

Suggest Corrections

I. 6x2+13x+21=0II. 5y2−22y+21=0

The correct option is C x>yEquation I 6x2+41x+63=0 ⇒6x2+27x+14x+63=0 ⇒3x(2x+9)+7(2x+9)=0 ⇒(3x+7)(2x+9)=0 ∴x=−73,x=−92 Equation II 4y2+8y+3=0 ⇒4y2+6y+2y+3=0 ⇒2y(2y+3)+1(2y+3)=0 ⇒(2y+1)(2y+3)=0 ∴y=−12,−32 Hence, x < y

$I . 6 x^{2} + 13 x + 21 = 0 I I . 5 y^{2} - 22 y + 21 = 0$