Question

Question 8 (i)
A bag contains 3 red balls and 5 black balls. A ball is drawn at random from the bag. What is the probability that the ball drawn is red?

Answer 1

The number of balls in the bag = 3 + 5 = 8.
Out of these 8 balls, one can be chosen in 8 ways.
$\therefore$ Total number of elementary events = 8

Since the bag contains 3 red balls, therefore, one red ball can be drawn in 3 ways.
$\therefore$ Favourable number of elementary events = 3

Hence, P (getting a red ball)
$=\frac{Favourablenumberofelementaryevents}{Totalnumberofelementaryevents}=\frac{3}{8}$