$I^{-}$ changes to $I_{3}^{-}$ in a reaction. What kind of reaction is it?

Oxidation

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Reduction

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Acid-Base

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Substitution

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Solution

The correct option is A Oxidation
$2 I^{-} \to I_{2} I^{-} - \to I_{3}^{-}$
$I^{-}$ is oxidised to $I_{2}$ , which is soluble in KI forming $K I_{3} (I_{3})^{-}$ . Thus, $I_{2}$ is formed by oxidation.

Suggest Corrections

Similar questions

I_{3}^{-}

I_{3}^{-} + A s O_{3}^{3 -} \to I^{-} + A s O_{4}^{3 -}

I_{2} + I^{-} \to I_{3}^{-}

I_{2} + I^{-} \to I_{3}^{-}

I_{2}

H_{2} O_{2} + 3 I^{-} + 2 H^{+} \to 2 H_{2} O + {I_{3}}^{-}

I^{-}

I_{2} + I^{-} \to I_{3}^{-}

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