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Question

I=ex(2cos2x+2sinxcosxcos2x)dx

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Solution

I=ex(2cos2x+2sinxcosxcos2x)dx

=ex(2sec2x+2tanx)dx

=ex2tanxdx+2exsec2xdx
=2extanx2exsec2xdx+2exsec2xdx+c [c being integrating constant] [Using integration by parts]

=2extanx+c.

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