Question

I.F. of $\frac{dy}{dx}+y\tan x={\cos }^{3}x$ is:

• A. ${\sec }^{2}x$
• B. $\cos x$
• C. $\cot x$
• D. secxsec⁡x

Answer 1

The correct option is D secxsec⁡x

$y^1+y^{\tan x}={\cos }^{3}x$
$I.F=e{}^{\int P\left(x\right)dx}$
$=e{}^{\int \tan dx}=e{}^{log\sec x}=\begin{array}{c}\sec x\end{array}$