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Question

I.F. of sinxdydx+ycosx=2sin2x cosx:

A
sinx
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B
cosx
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C
cotx
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D
secx
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Solution

The correct option is C sinx
dydx+ycotx=sin2x
I.F=eP(x)dx
=ecotxdx
=elog|sinx|
I.F=sinx

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