Question

$I.\frac{4}{\sqrt{x}}+\frac{7}{\sqrt{x}}=\sqrt{x}II.y^2-\frac{{11}^{\frac{5}{2}}}{\sqrt{y}}=0$

• A. if x > y
• B. if x ≥ y
• C. if x < y
• D. if x ≤ y
• E. if x = y or the relationship cannot be established

Answer 1

The correct option is E

if x = y or the relationship cannot be established

$I.\frac{4}{\sqrt{x}}+\frac{7}{\sqrt{x}}=\sqrt{x}Or\frac{4+7}{\sqrt{x}}=\sqrt{x}Or11=\sqrt{x}\times \sqrt{x}Orx=11II.y^2-\frac{{11}^{\frac{5}{2}}}{\sqrt{y}}=0Or\frac{y^{\frac{5}{2}}-{11}^{\frac{5}{2}}}{\sqrt{y}}=0Ory-11=0Ory=11So,x=y$