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Question

# I have a container that is 20cm tall and filled fully with water. The lift accelerates up at 10m/s/s. What is the pressure difference between the top surface of the water and the bottom of the container? Take density of water as 1000 kg/m3.

A

2×103 Pa

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B

8×103 Pa

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C

4×103 Pa

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D

16×103 Pa

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Solution

## The correct option is C 4×103 Pa Since the container is accelerating up, effective g will be g′=g+a=10+10=20m/s2 The pressure difference from top to bottom will be hρg′ = 0.2×1000×20 =4×103 Pa

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