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Question

# I have a container that is 20cm tall and filled fully with water. The lift accelerates up at 10 m/s2. What is the pressure difference between the top surface of the water and the bottom of the container(in pascal)? Take density of water as 1kg/lit.

A
2×104
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B
8×104
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C
4×104
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D
16×104
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Solution

## The correct option is C 4×104 Since the container is accelerating up, effective g will be g′=g+a=10 m/s2+10 m/s2=20 m/s2 The pressure difference from top to bottom will be hρg′ = 0.2×1000×20 =4×104 Pa

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