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Boyle's Law

I, II and III...

Question

I, II and III are three isotherms respectively at $T_{1}, T_{2}$ and $T_{3}$ temperature. The order of temperature will be?

T_{1} = T_{2} = T_{3}

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T_{1} < T_{2} < T_{3}

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T_{1} > T_{2} > T_{3}

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T_{1} > T_{2} = T_{3}

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Solution

The correct option is D $T_{1} > T_{2} > T_{3}$
From the graph, at constant $P$ ,
Volume at $T_{3} < V o l u m e a t T_{2} < v o l u m e a t T_{1}$
From Charle's law, we know that, $V \propto T$
$∴ T_{1} > T_{2} > T_{3}$

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