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Question

Im,n=10xm(logx)ndx, then Im,n is equal to 


  1. nn+1Im,n1
     

  2. -mn+1Im,n1
     

  3. -nm+1Im,n1

     

  4. mn+1Im,n1


Solution

The correct option is C

-nm+1Im,n1

 


Im,n=10xm(logx)ndx=(logx)n.xm+1m+11010n(logx)n1.1x.xm+1m+1dx=0nm+110xm(logx)n1dx=nm+1Im,n1

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