I.P. of sodium is 5.14 eV then I.P. of potassium will be :

equal to sodium

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.68 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

4.34 eV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

10.28 eV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 4.34 eV
I.P. of sodium is 5.14 eV then I.P. of potassium will be 4.34 eV. On moving down a group, the ionization potential decreases. Hence, the ionization potential of potassium should be lower than the ionization potential of sodium.

Suggest Corrections

Similar questions

I P_{1}, I P_{2}, I P_{3}

I P_{4}

7.5 e V, 25.6 e V, 48.6 e V

170.6 e V

I P_{1^{'}} I P_{2^{'}} I P_{3^{'}} I P_{4^{'}}

I P_{5}

7.1, 14.3, 34.5, 46.8, 162.2

The IP1, IP2, IP3, IP4 and IP5 of an element are 7.1, 14.3, 34.5, 46.8, 162.2 eV respectively. The element is likely to be -

If threshold wavelength for sodium is $6800 \circ A$ then the work function will be

Join BYJU'S Learning Program