(i) | Position vector →A | (1) | 2^i+^j |
(ii) | Postion vector →B | (2) | 3^i+3^j |
(iii) | Displacement →dAB | (3) | 5^i+4^j |
(iv) | Position vector of point of intersection of path 1 & path 2 | (4) | 4^i+3^j |
(i) - (3), (ii) - (1), (iii) - (2), (iv) - (4)
(i) From the diagram, you can see that A is at (5,4). ∴ position vector is 5^i+4^j.
(ii) Similarly, B is 2^i+^j.
(iii) →dAB is the displacement vector if you move from B to A. ∴→dAB=→A−→B
=5^i+4^j−(2^i+^j)
=3^i+3^j
You can also see that if you shift the origin to B, the position vector of A becomes, 3^i+3^j.
(iv) Point of intersection is at 4^i+3^j