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Exponential Representation for Irrational Numbers

Question 98i ...

Question

Simplify:
${(\frac{1}{4})}^{- 2} + {(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2}$

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Solution

Using law of exponents, $a^{- m} = \frac{1}{a^{m}}$
$∴ {(\frac{1}{4})}^{- 2} + {(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2} = (4)^{2} + (2)^{2} + (3)^{2} = 16 + 4 + 9 = 29$

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Question 98(i)

Simplify:
${(\frac{1}{4})}^{- 2} + {(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2}$

{(\frac{1}{2})}^{- 2} + {(\frac{1}{3})}^{- 2} + {(\frac{1}{4})}^{- 2}

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Exponential Representation for Irrational Numbers

Standard IX Mathematics

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