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Question

(i) The maximum value of sin(x+π6)+ cos (x+π6) in the interval (0,π/2) is attained when x =

A
π/12
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B
π/6
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C
π/3
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D
π/2
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Solution

The correct option is D π/12
sin(x+π6)+ cos (x+π6) =2cos(x+π6π4) = 2cos(xπ12)etc.
It is max., when x- π/12 =0 i.e, x= π/12

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