Question

Question 21(i)
Two dice are thrown together. Find the probability that the product of the numbers on the top of the dice is 6?

Answer 1

Number of total outcomes = 36
When product of the numbers on the top of the dice is 6.
So, the possible ways are (1,6), (2,3), (3,2) and (6,1).
Number of possible ways = 4
$\therefore$ Required probability $=\frac{4}{36}=\frac{1}{9}$