$I - V$ graph for a metallic wire at two different temperatures, $T_{1}$ and $T_{2}$ is a shown in the figure.
Which of the two temperature is lower and why?

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Solution

Slope of a V-I graph gives value of $1 / R$ , as we can see that the slope of graph 1 is greater than graph 2 ,so
$1 / R_{1} > 1 / R_{2}$
or $R_{2} > R_{1}$
we know that the resistance of metals increases with increase in temperature therefore
$T_{2} > T_{1}$
it means $T_{1}$ is lower because $R_{1}$ is smaller .

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I−V graph for a metallic wire at two different temperatures, T1 and T2 is a shown in the figure.Which of the two temperature is lower and why?

Slope of a V-I graph gives value of 1/R , as we can see that the slope of graph 1 is greater than graph 2 ,so 1/R1>1/R2or R2>R1we know that the resistance of metals increases with increase in temperature therefore T2>T1it means T1 is lower because R1 is smaller .

$I - V$ graph for a metallic wire at two different temperatures, $T_{1}$ and $T_{2}$ is a shown in the figure.
Which of the two temperature is lower and why?