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Byju's Answer

Standard XII

Physics

Semiconductors and Superconductors

I-V graph for...

Question

I-V graph for a mettallic wire at two different temperatures, $T_{1}$ and $T_{2}$ is as shown in the figure.

Which of the two temperature is lower and why?

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Solution

The slope of a V-I graph is given by the formula $\frac{I}{V} = \frac{1}{R}$ . Thus, the smaller the slope larger is the resistance. As the resistance of a metal increases with the increase in temperature, so resistance at $T_{2}$ is higher and lower at $T_{1}$ .
Therefore temperature $T_{2}$ is lower.

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I-V graph for a mettallic wire at two different temperatures, T1 and T2 is as shown in the figure. Which of the two temperature is lower and why?

The slope of a V-I graph is given by the formula IV=1R. Thus, the smaller the slope larger is the resistance. As the resistance of a metal increases with the increase in temperature, so resistance at T2 is higher and lower at T1. Therefore temperature T2 is lower.

I-V graph for a mettallic wire at two different temperatures, $T_{1}$ and $T_{2}$ is as shown in the figure.

Which of the two temperature is lower and why?