Question

$I.x^2-10x+24=0$
$II.y^2-9y+20=0$

• A. x > y
• B. x $\ge$ y
• C. x < y
• D. x $\le$ y
• E. x = y or the relationship cannot be established

Answer 1

The correct option is B x $\ge$ y

$I.x^2-10x+24=0$
$\Rightarrow x^2-6x-4x+24=0$
$\Rightarrow x(x-6)-4(x-6)=0$
$\Rightarrow (x-4)(x-6)=0$
$\therefore x=4or6$
$II.y^2-9y+20=0$
$\Rightarrow y^2-5y-4y+20=0$
$\Rightarrow y(y-5)-4(y-5)=0$
$\Rightarrow (y-4)(y-5)=0$
$\therefore y=4or5$
$\therefore x\ge y$