Question

I. $x^2=729$
II. $y=\sqrt{729}$

• A. If $x>y$
• B. If $x\ge y$
• C. If $x<y$
• D. If $x\le y$
• E. $x=y$ or the relationship cannot be established.

Answer 1

The correct option is E $x=y$ or the relationship cannot be established.

Equation I:-
$x^2=729\Rightarrow x^2=(27{)}^2$
$\Rightarrow x=27,-27$

Equation II:-
$y=\sqrt{729}$
$\Rightarrow y=\pm 27$
$\Rightarrow y=27,-27$
Hence, $x=y$