Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, she will get 8.

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Solution

Let the required no.be x

$\frac{x + 19}{5} = 8$

$x + 19 = 40$

$x = 40 - 19$

$x = 21$

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(d) When I subtracted 11 from twice a number, the result was 15.

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Ibenhal thinks of a number. If she adds 19 to it and divides the sum by 5, she will get 8.

Let the required no.be xx+195=8x+19=40x=40−19 x=21

Let the required no.be x

$\frac{x + 19}{5} = 8$

$x + 19 = 40$

$x = 40 - 19$

$x = 21$