Ice and water are placed in a closed container at a pressure of 1 atm and $273.15 K$ temperature. If the pressure of the system is increased by 2 atm keeping temperature constant, the correct observation would be:

the liquid phase disappears completely

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the amount of ice increases

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the solid phase (ice) disappears completely

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volume of the system increases

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Solution

The correct option is C the solid phase (ice) disappears completely
When the pressure will increase,

$H_{2} O (s) ⟶ H_{2} O (l)$ ,
As the volume of $H_{2} O (s)$ is more than the volume of $H_{2} O (l)$ so to decrease the volume of the system with an increase in pressure ice will melt into liquid water.

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Ice and water are placed in a closed container at a pressure of 1 atm and 273.15 K temperature. If the pressure of the system is increased by 2 atm keeping temperature constant, the correct observation would be:

The correct option is C the solid phase (ice) disappears completelyWhen the pressure will increase,H2O(s)⟶H2O(l), As the volume of H2O(s) is more than the volume of H2O(l) so to decrease the volume of the system with an increase in pressure ice will melt into liquid water.

Ice and water are placed in a closed container at a pressure of 1 atm and $273.15 K$ temperature. If the pressure of the system is increased by 2 atm keeping temperature constant, the correct observation would be: