Given, Density of ice is pi=0.917gcm3
Let the density of water bepw=1gmcm3.
Let the volume of the iceberg be V.
Weight of the iceberg W=pigV…(i)
x is the fraction of iceberg submerged in water, then the volume of water displaced:
Vs=xV
Buoyant force due to submerged part of iceberg
FB=pwgVs
At equilibrium:
FB=W
pwgVs=pigV
pwg(xV)=pigV
x=pipw=0.9171
x=0.917
Final Answer: 0.917