Identical springs of steel and copper (Ysteel>Ycopper) are equally stretched then:
A
Less work is done on copper spring
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B
Less work is done on steel spring
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C
Equal work is done on both the springs
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D
Data is incomplete
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Solution
The correct option is D Less work is done on steel spring Work done, W=12×F×ΔL For a given F W∝ΔL...(i) and ΔL=FLAY As F,A and L are constants ∴ΔL∝1Y...(ii) From (i) and (ii), we get W∝1Y ∴WsteelWcopper=YcopperYsteel
As Ycopper<Ysteel ∴Wsteel<Wcopper So, less work is done on steel spring