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Polyhalogen Compounds

Identify B in...

Question

Identify (B) in the following sequence of reaction.
$C H = C H C u_{2} C l_{2} + N H_{4} C l ⟶ A H C l (1 m o l e) ⟶ (B)$

C H_{3} C H_{2} C l

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C H_{2} = C H - C H_{2} C H_{2} C l

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H C = C - C | C l H - C H_{3}

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C H_{2} = C H - C l | C = C H_{2}

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Solution

The correct option is D $C H_{2} = C H - C l | C = C H_{2}$
$H C \equiv C H C u_{2} C l_{2} + N H_{4} C l - --------- \to$ $C H_{2} = C H - C \equiv C H (A)$
$C H_{2} = C H - C \equiv C H H C l - --- \to 1 m o l e C H_{2} = C H - C l | C = C H_{2} (B)$
Option D is correct.

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C H_{3} - C H_{2} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H ∣ C H_{3} - C H_{2} - C l

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C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{2} - C H_{2} - B r

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C H_{3} - C H ∣ C H_{3} - C H_{2} - C H_{2} - C l a n d C H_{3} - C H_{3} ∣ C ∣ C H_{3} - C H_{2} C l

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C H_{3} - C H_{2} - C H_{2} - B r ∣ C H - C H_{3} a n d C H_{3} - C H_{3} ∣ C H - C H_{2} - B r ∣ C H - C H_{3}

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c o n c . H C l :

(a) C H_{3} - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{2} - C l

(b) C H_{3} - C H_{3} | C | C H_{3} - C H_{2} O H A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C H_{1} | C | C H_{3} - C H_{2} - C H_{3}

(c) C H_{3} - O H | C | C H_{3} - C H_{3} A n h y Z n C l_{2} / △ - -------- \to C H_{3} - C l | C | C H_{3} - C H_{3}

(d) C H_{2} = C H - C H_{2} - O H A n h y Z n C l_{2} / △ - -------- \to C H_{2} = C H - C H_{2} - C l

A . C H_{3} - C H = C H_{2} + H C l ⟶ C H_{3} - C | C l H - C H_{3}

B . C H_{3} - C H = C H_{2} + H B r ⟶ C H_{3} - C H_{2} - C H_{2} B r

C . C H_{3} - C H = C H_{2} + H B r p e r o x i d e - ---- \to C H_{3} - C H_{2} - C H_{2} - B r

D . C H_{3} - C H = C H_{2} + H I p e r o x i d e - ---- \to C H_{3} - C | I H - C H_{3}

A g N O_{3}

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