Identify product Z in the following reaction sequence:
$H_{2} C = C H C H_{2} B r N a C N - --- \to Y 1.. C_{6} H_{5} M g B r, d i e t h t e t h e r - --------------- \to 2. H_{3} O^{+} Z$

H_{2} C = C H C H_{2} O | | C C_{6} H_{5}

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H_{2} C = C H C H_{2} N H O | | C C_{6} H_{5}

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H_{2} C = C H C H_{2} O H | C H C_{6} H_{5}

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H_{2} C = C H C H_{2} N H_{2} | C H C_{6} H_{5}

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Solution

The correct option is C $H_{2} C = C H C H_{2} O H | C H C_{6} H_{5}$
$C H_{2} = C H C H_{2} B r + N a C N \to C H_{2} = C H_{2} C N$

$C H_{2} = C H C H_{2} C N + C_{6} H_{5} M g B r / H_{3} O^{+} \to C H_{2} = C H C H_{2} C H (O H) C_{6} H_{5}$

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Similar questions

H_{2} C = C H {C H}_{2} B r N a C N - --- \to Y 1. C_{6} H_{5} M g B r - ------- \to 2. H_{3} O^{+} Z

H - C \equiv C^{-}, H_{2} C = - C H

^{-} C H_{3}

H_{2} C = {C H C H}_{3}

H_{2} C = C H C l

H_{2} C = C H - C_{6} H_{5}

H_{2} C = {C H C O}_{2} {C H}_{3}

- E

$B r C H_{2} C H B r C H_{2} B r a l c . K O H - ---- \to [X] C H_{3} O^{-} - --- \to Y; [X]$ and [Y] respectively are

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