Identify the compound A, B & C in the following sequence of reaction and rewrite the complete equation
$A R a n e y N i - ----- \to Δ B {B r}_{2} / {A l B r}_{3} - ----- \to Δ C N a / d r y e t h e r - ------- \to Δ n - B u t a n e$

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Solution

Solution:-
$C H_{2} = C H_{2} Ethene Raney Ni / Δ - ------ \to C H_{3} - C H_{3} Ethane {B r}_{2} / A l {B r}_{3} / Δ - ------- \to - H B r C H_{3} - C H_{2} - B r Ethyl bromide N a / dry ether / Δ - --------- \to - N a B r C H_{3} - C H_{2} - C H_{2} - C H_{3} n-Butane$
Compound $C$ reacts with $N a / d r y e t h e r$ to give n-butane. This reaction is Wurtz synthesis reaction.
Thus compound $C$ must be ethyl haliSinceInce the compound $B$ undergoes bromination to form compound $C$ , thus compound $C$ must be ethyl bromide.
Now compound $B$ give ethyl bromide on bromination thus it must be ethane.
Now compound $A$ reacts with Raney Ni i.e. it undergoes hydrogenation reaction to form ethane. Thus compound $A$ must be ethene.
Hence the compounds $A, B$ and $C$ are ethene, ethane and ethyl bromide respectively.

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