Identify the compound which can show geometrical isomerism.

C H_{2} = C H - C | H OH - C H_{2} - C H_{3}

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H_{2} C = C H - C H_{2} - C | H O H - C H_{3}

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C H_{3} - C H = C H - C H_{2} - C H_{2} - O H

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H_{2} C = C H_{3} | C - C | H OH - C H_{3}

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Solution

The correct option is D $C H_{3} - C H = C H - C H_{2} - C H_{2} - O H$
$C H_{3} - C H = C H - C H_{2} - C H_{2} - O H$ , in this molecule each double bonded carbon have two different group attached with it so it shows geometrical isomerism.
Geometrical isomerism is a type of stereo configurational isomerism
When two compounds have the same molecular formula and the same structural formula but differ in the spatial arrangement of atoms or group of atoms due to the restricted rotation of double bonds (about single bond in the case of cyclic compounds), they are said to exhibit geometrical isomerism. Such compounds are called geometrical isomers. They are also called cis-trans isomers.

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Similar questions

H_{2} C = C H - C H | O H - {C H}_{2} - {C H}_{2} - {C H}_{3}

C H_{3} - C H_{2} - C H_{2} - O H

C H_{3} - C H = C H - O H

C H_{3} - C H = C H - C H_{2} - O H

C H_{3} - C H = C H - O H

C H_{3} - C H_{2} - O H | C H - C H_{2} - C H_{2} - C | H C H_{3} - C H_{2} - C H_{3}

C H_{3} - O H | C H - C H_{2} - C H_{2} - O | | C - C H_{3} \to C H_{3} - O H | C H - (C H_{2})_{3} - C H_{3}

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