Identify the conjugate acids and bases in the following equation:
$N H_{3} + H_{2} O ⇌ N H_{4}^{+} + O H^{-}$

(H_{2} O, O H^{-})

and

(N H_{2}^{+}, N H_{3})

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(H_{2} O, O H^{-})

and

(N H_{4}^{+}, N H_{2}^{2 -})

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(H_{2} O, O H)

and

(N H_{3}, N H_{4})

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(H_{2} O, O H^{-})

and

(N H_{4}^{+}, N H_{3})

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Solution

The correct option is B $(H_{2} O, O H^{-})$ and $(N H_{4}^{+}, N H_{3})$
Conjugate acids and bases differ by one proton only.
$N H_{3}$ is a base. It accepts a proton to form $N H_{4}^{+}$ ion which is conjugate acid.
$N H_{3} + H^{+} \to N H_{4}^{+}$ .
Hence, $(N H_{4}^{+}, N H_{3})$ is a conjugate acid, base pair.

$O H^{-}$ is a base. It accepts a proton to form $H_{2} O$ which is conjugate acid.
$O H^{-} + H^{+} \to H_{2} O$ .
Hence, $(H_{2} O, O H^{-})$ is a conjugate acid, base pair.

Hence, option $D$ is correct.

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Similar questions

N H_{3} + H_{2} O \to N H_{4}^{+} + O H^{-}

N H_{3} + H_{2} O \to N H_{4}^{+} + O H^{-}

H_{2} O + N H_{3} \to N H_{4}^{+} + O H^{-}

N H_{3} + H_{2} O \to N H_{4}^{+} + O H^{-} i s :

H C l + H_{2} O \to H_{3} O^{+} + C l^{-}

H_{2} O + N_{3} \to O H^{-} + N H_{4}^{-}

H S^{-} + H C l \to C l^{-} + H_{2} S

H S^{-} + N H_{3} \to N H_{4}^{+} + S^{2 -}

H C l + N a O H \to N a C l + H_{2} O

N a C l + H_{2} O \to H C l + N a O H

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