Question

In the reaction $N{H}_3+H_{2}O\to N{H}_4^{+}+O{H}^{-}$, the conjugate acid-base pair is:

• A. $N{H}_3$ and $H_{2}O$
• B. $N{H}_3$ and $O{H}^{-}$
• C. $H_{2}O$ and $N{H}_4^{+}$
• D. $N{H}_4^{+}$ and $N{H}_3$

Answer 1

The correct option is D $N{H}_4^{+}$ and $N{H}_3$

A conjugate acid-base pair differs by a single proton.

A conjugate acid is formed when a proton is accepted by a Bronsted base, while a conjugate base is formed when a proton is donated by a Bronsted acid.

The reaction is given below:

$N{H}_3+H_{2}O\to N{H}_4^{+}+O{H}^{-}$

Here, we have two conjugate acid-base pairs. They are as follows:

$1.$ $N{H}_4^{+}$ and $N{H}_3$

$2.$ $H_{2}O$ and $O{H}^{-}$

Hence, among the four options given, option D is the correct answer.