The correct option is A I, IV, III, II
weightequivalent weight=no.ofequivalent
=no.ofmoles×N−factor
∴ Equivalent weightα1N−factor
α1no. of electron required to reduce
Equivalent weight=M.W.N−factor
∴forAg=1081
forZn=662=33
forCu=642=32
forH=12=0.5
∴olderisAg,Zn,Cu,H