Identify the correct order of solubility of ${N a}_{2} S, C u S$ and $Z n S$ in aqueous medium.

C u S > Z n S > {N a}_{2} S

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Z n S > {N a}_{2} S > C u S

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{N a}_{2} S > C u S > Z n S

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{N a}_{2} S > Z n S > C u S

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Solution

The correct option is D ${N a}_{2} S > Z n S > C u S$
The correct order of solubility of ${N a}_{2} S, C u S$ and $Z n S$ in aqueous medium is ${N a}_{2} S > Z n S > C u S$ . Sodium salts are highly soluble in water and thus of ${N a}_{2} S$ shows highest solubility. The $K_{s p}$ value of $C u S$ is less than $Z n S$ and thus, $Z n S$ is more soluble than the former.

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The cell representation of the given reaction is:
Zn(s) + Cu²⁺ → Zn²⁺ + Cu(s)

The standard reducation potentials of

$Z n^{2 +} | Z n, C u^{2 +} | C u$ and $A g^{+} | A g$

are respectively -0.76, 0.34 and 0.8 V. The following cells were constructed.

a) $Z n | Z n^{2 +} | | C u^{2 +} | C u$

b) $Z n | Z n^{2 +} | | A g^{+} | A g$

c) $C u | C u^{2 +} | | A g^{+} | A g$

What is the correct order $E {^{0}}_{c e l l}$ of these cells?

{Z n}_{(s)} + {C u}^{+ 2}_{(a q)} ⇌ {Z n}^{+ 2}_{(a q)} + {C u}_{(s)}

{Z n}_{(s)}

{C u}_{(s)}

{C u}^{+ 2}_{(a q)}

{Z n}^{+ 2}_{(a q)}

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