Question

Identify the correct set of enzymes by examining their action on substrates
I. $AH+B\to A+BH\left(NADH\right)$
II. Transfers functional group and includes 'Kinases'.
III. $A-B+H_{2}O\to A-OH+B-H$
IV. Breaks bonds without using water (formation of double bonds).
V. Conversion of compounds into its isomer $A-B\to B-A$

VI. Joins different compounds. $AB+C\to AB-C$

• A. I. Transferases II. Hydrolases III. Lyases IV. Isomerases V. Ligases VI. Reductases
• B. I. Reductases II. Transferases III. Hydrolases IV. Lyases V. Isomerases VI. Ligases
• C. I. Lyases II. Isomerases III. Ligases IV. Reductases V. Transferases VI. Hydrolases
• D. I. Isomerases II. Ligases III. Reductases IV. Transferases V. Hydrolases VI. Lyases

Answer 1

The correct option is B

I. Reductases II. Transferases III. Hydrolases IV. Lyases V. Isomerases VI. Ligases

The correct set of enzymes by their order of action on substrates, is :

I. $AH+B\to A+BH\left(NADH\right)$; is a reaction mediated by oxidoreductases. Reductases transfer electrons from a donor to an acceptor.

II. Transferases, which include kinases, mediate the transfer of functional groups.

III. Breaking of bonds by using $H_{2}O$; $A-B+H_{2}O\to A-OH+B-H$ is mediated by Hydrolases.

IV. Lyases mediate the breaking of bonds without using hydrolysis.

V. Isomerases mediate the conversion of a compound to form its isomer. $A-B\to B-A$

VI. Ligases mediate the joining of compounds. $AB+C\to AB-C$