The correct options are
A compound (A) is formed through
SN reaction
B compound (C) on reduction with
LiAlH4 forms a product which on dehydration given cyclohexene.
D compound (C) on Schmidt's reaction gives a product which reacts with
HNO2 to give (D) as major product. compound (D) on dehydration gives cyclopentene
The statements (A), (B) and (D) are correct. The statement (C) is incorrect.
(A) Compound (A) is formed through nucleophilic substitution reaction. Chlorine atoms are replaced with cyanide groups.
(B) Compound (C) (cyclopentanecarboxylic acid) on reduction with LiAIH4 forms cyclopentylmethanol which on dehydration gives cyclohexene. Dehydration step involves rearrangement in which five member ring expands into six member ring.
(C) Compound (A) requires one (not two) mole of hydrogen for complete reduction.
(D) Compound (C) (cyclopentanecarboxylic acid) on Schmidt's reaction gives cyclopentanamine (−COOH group is replaced with −NH2 group) which reacts with HNO2 to give (D) (cyclopentanol) as major product. Compound (D) (cyclopentanol) on dehydration gives cyclopentene.