Identify the greater number, wherever possible, in the following?
$2^{8}$ or $8^{2}$ .

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Solution

$2^{8} o r 8^{2} \Rightarrow 2^{8} = 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 \times 2 = 256 \Rightarrow 8^{2} = 8 \times 8 = 64 ∴ 2^{8} > 8^{2}$

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