Identify the oxidant and the reductant in the following reaction respectively: 3Na2HAsO3+KBrO3+6HCl→6NaCl+KBr+3H3AsO4
A
Na2HAsO3&KBrO3
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B
KBrO3&Na2HAsO3
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C
HCl&KBr
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D
KBr&HCl
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Solution
The correct option is BKBrO3&Na2HAsO3 (+3)3Na2HAsO3+(+5)KBrO3+6HCl→6NaCl+(−1)KBr+3(+5)H3AsO4. It is a redox reaction. Oxidant are compound which get reduced and oxide the other compound. Reductant are compound which get oxidised and reduce the others. Here As+3 lose 2 electron and get oxidised to +5 oxidation state. Hence Na2HAsO3 is an reducing agent or reductant. (+3)Na2HAsO3(reductant)→(+5)H3AsO4(oxidation half).
Also Br+5 gains 6 electron and get reduced to -1 oxidation state. Hence KBrO3 is the oxidising agent or oxidant. (+5)KBrO3(oxidant)→(−1)KBr(reduction half half).