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Nitrogen

Identify the ...

Question

Identify the pair of binary corresponds in which nitrogen exhibits the lowest and the highest oxidation state.

N H_{3}, N O_{2}

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N_{3} H, N_{2} O_{5}

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N_{2}, H N O_{3}

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N_{2} O, N_{2} O_{5}

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Solution

The correct option is B $N_{3} H, N_{2} O_{5}$
Oxidation of nitrogen in $N_{3} H$ is $- \frac{1}{3}$ , which is the lowest possible.
Oxidation of nitrogen in $N_{2} O_{5}$ is $+ 5$ which is the highest possible.

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Similar questions

{H N O}_{3}

N_{2} O, N O, N_{2} O_{5}

N_{2} O_{5} ⟶ 2 N O_{2} + 1 / 2 O_{2}

- \frac{d [N_{2} O_{5}]}{d t} = k_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = k_{2} [N_{2} O_{5}]

\frac{d [O_{2}]}{d t} = k_{3} [N_{2} O_{5}]

k_{1}, k_{2}

k_{3}

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2} .

G i v e n : - \frac{d [N_{2} O_{5}]}{d t} = K_{1} [N_{2} O_{5}]

\frac{d [N O_{2}]}{d t} = K_{2} [N_{2} O_{5}]

A n d \frac{d [O_{2}]}{d t} = K_{3} [N_{2} O_{5}]

The relation between $K_{1}, K_{2}$ and $K_{3}$ is

N_{2} O_{5} \to 2 N O_{2} + \frac{1}{2} O_{2},

\frac{- d}{d t} [N_{2} O_{5}] = k_{1} [N_{2} O_{5}], \frac{d}{d t} [N O_{2}] = k_{2} [N_{2} O_{5}] a n d

\frac{d}{d t} [O_{2}] = k_{3} [N_{2} O_{3}],

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