Identify the product of the reaction when molecule undergoes ozonolysis:

I is only product.

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I and III

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I and IV

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

II and IV

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C I and IV
The products for the ozonolysis are represented by structures I and IV. They are cyclopentanone and acetone respectively. A $C = C$ double bond is broken and the $C$ atoms attached to $C = C$ double bond are oxidized to carbonyl groups.

Suggest Corrections

Similar questions

Which of the following alkyl halide undergo rearrangement in $S_{N} 1$ reaction

Q. Write the product(s) formed when
(i) 2-Bromopropane undergoes dehydrohalogenation reaction.
(ii) Chlorobenzene undergoes nitration reaction.
(iii) Methylbromide is treated with

K C N

In the product $5 m a b$ ,

(i) $5$ is the numerical coefficient of $m a b$ .

(ii) the coefficient of $a b$ is $5 m$ .

(iii) $m$ , $a$ and $b$ are the only factors.

Q. Identify the reaction, give example with equation.

(I)

products become hot/warm

(I I)

product is in soluble

(I I I)

product cools down.

Question 12
Poultry farming is undertaken to raise following

(i) Egg production
(ii) Feather production
(iii) Chicken meat
(iv) Milk production

(a) (i) and (iii)
(b) (i) and (ii)
(c) (ii) and (iii)
(d) (iii) and (iv)

Join BYJU'S Learning Program

Identify the product of the reaction when molecule undergoes ozonolysis:

The correct option is C I and IVThe products for the ozonolysis are represented by structures I and IV. They are cyclopentanone and acetone respectively. A C=C double bond is broken and the C atoms attached to C=C double bond are oxidized to carbonyl groups.

The correct option is C I and IV
The products for the ozonolysis are represented by structures I and IV. They are cyclopentanone and acetone respectively. A $C = C$ double bond is broken and the $C$ atoms attached to $C = C$ double bond are oxidized to carbonyl groups.