Identify the resistance from which 5 Amp current is flowing.
A
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B
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C
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Solution
The correct option is C According to the kirchhoff’s voltage law (KVL) - the sum of all voltages around a closed loop in any circuit must be equal to zero.
Taking loop ABCDA
Using Kirchoff's law's sign conventions as shown below:We are assuming clockwise current as positive.
Applying KVL: 10−i2×2=0 i2=5amp
Hence, 2 ohm resistance will have 5 amp of current.
lets take other loop to verify the answer
Taking loop AEFGA −10−i3×5+2−i3×3=0 i3×8=−8 i3=−1A
Other two resistances will have 1 A current but in opposite direction as assumed. So 1 A will flow in anticlockwise direction in the loop AEFGA.