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B
(−∞,−5)∪(5,∞)
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C
(5,∞)
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D
(−∞,−5)∪(−3,3)∪(5,∞)
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Solution
The correct option is B(−∞,−5)∪(5,∞) 1|x|−3<12 Solution: Since, 1|x|−3<12 ∴|x|−3>2 ∴|x|>5 ∴x<−5 and x>5 Hence, solution set for 1|x|−3<12 is (−∞,−5)∪(5,∞)