Identify the substance oxidized, substance reduced, oxidizing agent and reducing agent in the given reaction
$H_{2} S + B r_{2} \to 2 H B r + S$

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Solution

$H_{2} S$ is oxidized to $‘ S^{'}$ , $B r_{2}$ is reduced to $H B r . B r_{2}$ oxidizes $H_{2} S$ so it is the oxidizing agent, $H_{2} S$ reduces $B r_{2}$ to $H B r$ so it is the reducing agent.

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H_{2} S + B r_{2} \to 2 H B r + S

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Identify the substance oxidized, substance reduced, oxidizing agent and reducing agent in the given reaction H2S+Br2→2HBr+S

H2S is oxidized to ‘S′, Br2 is reduced to HBr.Br2 oxidizes H2S so it is the oxidizing agent, H2S reduces Br2 to HBr so it is the reducing agent.

Identify the substance oxidized, substance reduced, oxidizing agent and reducing agent in the given reaction
$H_{2} S + B r_{2} \to 2 H B r + S$

$H_{2} S$ is oxidized to $‘ S^{'}$ , $B r_{2}$ is reduced to $H B r . B r_{2}$ oxidizes $H_{2} S$ so it is the oxidizing agent, $H_{2} S$ reduces $B r_{2}$ to $H B r$ so it is the reducing agent.