Identify the substance oxidized,substance reduced ,oxidizing agent and reducing agent :
$M n O_{2} + 4 H C L \to M n C l_{2} + 2 H_{2} O + C l_{2}$

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Solution

$M n O_{2} + 4 H C l ⟶ M n C l_{2} + 2 H_{2} O + C l_{2}$
Oxidation state: $+ 4$ $- 1$ $+ 2$ $0$
Increase in oxidation state $=$ Oxidation $\Rightarrow$
As chlorine increases from $- 1 ⟶ 0 \Rightarrow$ (Oxidation of $H C l$ )
Decrease in oxidation state $=$ Reduction $\Rightarrow$ As manganese decreases from $+ 4 \to + 2 \Rightarrow$ (Reduction of $M n O_{2}$ )
$\Rightarrow M n O_{2}$ is reduced, $H C l$ is oxidized, $M n O_{2}$ is oxidizing agent, $H C l$ is reducing agent.

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Similar questions

Identify the substance oxidized, substance reduced, oxidising agent and reducing agent.
$M n O_{2}$ + $4 H C l$ $\to$ $M n {C l}_{2}$ + $2 H_{2} O$ + ${C l}_{2}$ .

Q. In the following reactions, identify the oxidising agent and the reducing agent.

4 H C l + M n O_{2} \to M n C l_{2} + 2 H_{2} O + C l_{2}

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4 H C l + M n O_{2} \to M n C l_{2} + 2 H_{2} O + C l_{2}

Q. (a) Define (i) oxidation, and (ii) reduction.
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MnO₂ + 4HCl → MnCl₂+ Cl₂+ 2H₂O

Q. Which substance/ion is oxidised and which substance/ion is reduced in the following reaction?

M n O_{2} + 4 H C l \to M n C l_{2} + 2 H_{2} O + C l_{2}

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Identify the substance oxidized,substance reduced ,oxidizing agent and reducing agent :MnO2+4HCL→MnCl2+2H2O+Cl2

Identify the substance oxidized,substance reduced ,oxidizing agent and reducing agent :
$M n O_{2} + 4 H C L \to M n C l_{2} + 2 H_{2} O + C l_{2}$