The correct option is
A Floral diagram of family Brassicaeeae
The diagram is showing sepals and petals as 4 free and are arranged in valvate aestivation and in cross form. Hence, the given diagram contains cruciform corolla. The androecium are 6 in number and are arranged in two whorls as 4 in inner whorl and 2 in outer whorl. The central ovary shown is bilocular.
Flowers of family Solanaceae are pentamerous i.e.
sepals, petals and stamens are present in the set of five.
In flowers of Euphorbiaceae family, sometimes corolla is absent and sometimes sepals, petals are present in set of five.
Flowers of family Liliaceae are composed of 6 tepals (sepals and petals are indistinguishable), 6 stamens in single whorl and trilocular ovary.
Flowers of family Brassicaeeae shows cruciform corolla, 6 stamens in two whorls (4+2) and unilocular ovary which becomes bilocular due to septum.
Thus, the correct answer is option A.