Question

Identify (X) to (Z) in the following sequence of reactions -

$CaO+C\stackrel{{2000}^{\circ }C}{\to }\left(X\right)+\left(Y\right){1100}^{\circ }C\downarrow +N_2\left(z\right)\stackrel{hydrolysis}{\to }\left(P\right)\text{gas}$

• A. $\left(X\right)\equiv Ca{C}_2\left(Y\right)\equiv CO\left(Z\right)\equiv C{a}_3{N}_2\left(P\right)\equiv N{H}_3$
• B. $\left(X\right)\equiv Ca{C}_2\left(Y\right)\equiv C\left(Z\right)\equiv Ca\left(N{H}_2\right)2\left(P\right)\equiv N{H}_3$
• C. $\left(X\right)\equiv Ca{C}_2\left(Y\right)\equiv C\left(Z\right)\equiv CaC{N}_2\left(P\right)\equiv N{H}_3$
• D. $\left(X\right)\equiv Ca{C}_2\left(Y\right)\equiv CO\left(Z\right)\equiv CaC{N}_2\left(P\right)\equiv N{H}_3$

Answer 1

The correct option is D

$\left(X\right)\equiv Ca{C}_2\left(Y\right)\equiv CO\left(Z\right)\equiv CaC{N}_2\left(P\right)\equiv N{H}_3$

X = $Ca{C}_2$ , heating calcium carbide with $N_2$ gives calcium cyanamide $\left(CaC{N}_2\right)$, which in turn liberates $N{H}_3$ on hydrolysis